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21x^2-44x+4=0
a = 21; b = -44; c = +4;
Δ = b2-4ac
Δ = -442-4·21·4
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-40}{2*21}=\frac{4}{42} =2/21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+40}{2*21}=\frac{84}{42} =2 $
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